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Push an oscillator harder so it swings wider — does it now tick slower, having more distance to cover, or stay perfectly on beat? Galileo timed a swinging chandelier against his own pulse to find out.
Push an oscillator harder so it swings wider — does it now tick slower, having more distance to cover, or stay perfectly on beat? Galileo timed a swinging chandelier against his own pulse to find out.
The answer is the surprise that runs every clock: the period doesn't depend on the size of the swing. A wider swing means more distance, but also more energy and more speed — and the two cancel exactly.
In simple harmonic motion the restoring force is proportional to displacement and always points back toward equilibrium: F = −kx. The period depends on mass and stiffness — but NOT on amplitude. That amplitude-independence is the signature of SHM.
Hooke's Law F = −kx is the engine: the minus sign keeps the force pointing back toward equilibrium, and its size grows with displacement. Feeding it into Newton's second law gives T = 2π√(m/k). Heavier mass → longer period (harder to accelerate); stiffer spring → shorter period (snaps back faster). Amplitude is absent, so a small swing and a large swing share the same period. Amplitude instead sets the energy: total , so stretching twice as far stores four times the energy. The mass hits top speed at equilibrium, v_max = Aω, where ω = √(k/m). **Limiting case:** at the turning points the speed is zero and the force is maximal; at the centre it's the reverse — and the period never contains : bigger swings travel faster and arrive on time. **Connect it:** SHM is Hooke's law fed into Newton's second — — and it is also the shadow of uniform circular motion projected onto one axis, which is where the and come from.
Thinking the amplitude changes the period — for a mass–spring the period depends only on m and k, not on how far you pull it.