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All lessons Mechanics22 min

The Pendulum

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Hook
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Interactive simulation
01

Hook

A grandfather clock's heartbeat is one swinging pendulum — yet whether it sweeps a wide arc or barely nudges off vertical, each swing takes the same time. How can the period not care about the size of the swing? And does a heavier bob speed it up or slow it down?

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Spoilers

The Pendulum — summary and key formula

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The question

A grandfather clock's heartbeat is one swinging pendulum — yet whether it sweeps a wide arc or barely nudges off vertical, each swing takes the same time. How can the period not care about the size of the swing? And does a heavier bob speed it up or slow it down?

Galileo allegedly spotted this watching a chandelier in Pisa Cathedral, timing it against his pulse. The bob's weight doesn't matter either — this isochronism made pendulums the world's best clocks for three centuries.

The key idea

A pendulum swings because gravity has a component along the arc that always points back toward the lowest point. For small angles (under about 15°) this restoring force is very nearly proportional to displacement — making the pendulum a simple harmonic oscillator.

The striking feature is what's absent. Mass doesn't appear: heavy and light bobs on equal strings swing in unison, because restoring force and inertia both scale with mass and cancel — exactly as in free fall. Amplitude doesn't appear either, as long as the swing stays small (the approximation sin θ ≈ θ is what keeps the motion harmonic; past ~20° the real period runs slightly long). On Earth a 1 m pendulum gives T≈2.0sT \approx 2.0 sT≈2.0s — one second out, one second back. This near-coincidence was once proposed as a definition of the metre. **All forms:** T=2πL/g⇒L=g (T/2π)2T = 2\pi\sqrt{L/g} \Rightarrow L = g\,(T/2\pi)^2T=2πL/g​⇒L=g(T/2π)2, f=1/Tf = 1/Tf=1/T. **Limiting case:** the formula is the small-angle limit (sin⁡θ≈θ\sin\theta \approx \thetasinθ≈θ) — at 30°30°30° the true period is already ≈1.7%\approx 1.7\%≈1.7% longer, and mmm never appears at all. **Connect it:** for small swings the restoring force is F≈−(mg/L)xF \approx -(mg/L)xF≈−(mg/L)x — Hooke's law in disguise with k=mg/Lk = mg/Lk=mg/L; substitute into T=2πm/kT = 2\pi\sqrt{m/k}T=2πm/k​ and the pendulum formula falls out.

The formula

T=2πLgT = 2\pi\sqrt{\dfrac{L}{g}}T=2πgL​​
  • ·T = period (one full back-and-forth swing) in seconds; L = length from pivot to the bob's centre of mass in metres; g = gravitational field strength (9.81 m/s² on Earth). Notice what's MISSING: no mass
  • ·no amplitude.

Common mistake

Thinking a heavier bob or wider swing changes the period — for small swings it depends only on length and g, not on mass or amplitude.

What to remember

  • ·Pendulum period T = 2π√(L/g): a longer pendulum swings slower.
  • ·Mass and (small) amplitude don't affect the period.
  • ·This isochronism made pendulums the heart of accurate clocks.