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All lessons Mechanics22 min

Hooke's Law and Springs

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Hook

A bungee cord barely resists at first, then yanks hard at the bottom. A trampoline gives little from a small dip but launches you from a deep one. In every case, the more you deform it, the harder it pushes back. Is there one rule behind all of this?

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Spoilers

Hooke's Law and Springs — summary and key formula

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The question

A bungee cord barely resists at first, then yanks hard at the bottom. A trampoline gives little from a small dip but launches you from a deep one. In every case, the more you deform it, the harder it pushes back. Is there one rule behind all of this?

Hooke found it in 1676: double the stretch, double the force. But the ENERGY stored grows with the SQUARE of the stretch — which is why twice the speed does four times the crash damage.

The key idea

Hooke's Law: a spring's force is proportional to how far it is stretched or compressed from its natural length, and always points back toward that length (a restoring force). The constant k measures stiffness.

Written fully as F = −kx, the minus sign says the force OPPOSES the displacement — stretch right, it pulls left. That permanent tug toward equilibrium is what makes a spring oscillate (the SHM tab) instead of sitting deformed. The stored elastic energy is PE = ½kx² — note the SQUARE, the source of the '4× energy for 2× stretch' result. That energy is handed back as the spring relaxes, which is how bows and catapults work. Push past the elastic limit, though, and the material deforms permanently — Hooke's Law no longer applies. **All forms:** F=kx⇒k=F/x⇒x=F/kF = kx \Rightarrow k = F/x \Rightarrow x = F/kF=kx⇒k=F/x⇒x=F/k, with stored energy E=12kx2E = \tfrac{1}{2}kx^2E=21​kx2. **Limiting case:** the law holds only up to the limit of proportionality — past it the FFF–xxx line bends and the spring keeps a permanent stretch; the straight line is the whole law. **Connect it:** feed F=−kxF = -kxF=−kx into ΣF=ma\Sigma F = maΣF=ma and you get a=−(k/m)xa = -(k/m)xa=−(k/m)x — Hooke's law is the engine of simple harmonic motion.

The formula

F=kxF = kxF=kx
  • ·F = restoring force (N)
  • ·k = spring constant / stiffness (N/m — newtons per metre of stretch)
  • ·x = extension or compression FROM the natural length (m)
  • ·not the total length

Common mistake

Forgetting that x is the extension FROM the natural length (not the total length), and that Hooke's law only holds up to the elastic limit.

What to remember

  • ·Spring force is proportional to extension: F = kx (k = stiffness in N/m).
  • ·x is measured from the natural, unstretched length.
  • ·Stored energy = ½kx² = the triangular area under the F–x line.