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All lessons Mechanics28 min

Motion and Its Graphs

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Hook
02
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03
Formalize
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Interactive simulation
01

Hook

A crash investigator has no video of the accident — only the car's velocity–time trace on a single sheet of paper. From the shape of that one line she states how hard the driver braked, how far the car skidded, and how fast it was still going when it reached the crossing. None of those numbers is written anywhere on the graph. Where are they hiding?

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Spoilers

Motion and Its Graphs — summary and key formula

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The question

A crash investigator has no video of the accident — only the car's velocity–time trace on a single sheet of paper. From the shape of that one line she states how hard the driver braked, how far the car skidded, and how fast it was still going when it reached the crossing. None of those numbers is written anywhere on the graph. Where are they hiding?

In the geometry. The steepness of the line is the acceleration — the rate the velocity changes, and the thing your body actually feels in a braking car. The area underneath it is the distance covered. Learn to read those two features and a single line tells you the whole story of a journey, including the part nobody witnessed.

The key idea

Position tells you where something is; velocity tells you how fast that position is changing, with a direction attached; acceleration tells you how fast the velocity is changing. Each is the rate of change of the one before it, and 'change divided by time' is exactly what the steepness of a line means — which is why one motion drawn as three stacked graphs carries velocity in the slope of the first and acceleration in the slope of the second. Run the chain backwards and division becomes area: the area under a velocity–time line is the distance covered.

Speed and velocity part company as soon as direction matters: drive out and back and your average speed is healthy while your average velocity is exactly zero, because displacement returned to zero. The unit m/s² means 'm/s of speed gained each second'; a negative value means velocity is dropping. Near Earth, gravity gives everything 9.8 m/s29.8\,\text{m/s}^29.8m/s2 downward. Read graphs by shape: a flat x–t line = at rest; a straight slanted x–t line = constant velocity; an x–t curve that steepens = speeding up. On the v–t graph, flat = constant velocity, sloping up = speeding up, sloping down = slowing down, and the area underneath always gives the distance — a rectangle (base × height) for steady velocity, a triangle (12×\tfrac12 \times21​× base ×\times× height) for a straight ramp. Stopping distance is both at once: d=vtr+v2/2ad = v t_r + v^2/2ad=vtr​+v2/2a, a rectangle plus a triangle. **Limiting case:** a=0a = 0a=0 is not 'stopped' — it is unchanging velocity, which flattens the v–t line and straightens the x–t line. And a closed path pins average velocity to exactly zero however fast you went, while average speed notices nothing. **Watch out:** a flat line means OPPOSITE things on the two graphs — flat x–t is stopped, flat v–t is cruising — so always check which graph you are reading. **Connect it:** the three plots are one motion differentiated twice, and areas walk you back up the chain. Multiply that slope by mass and kinematics becomes dynamics: F=maF = maF=ma.

The formula

v=ΔxΔta=ΔvΔtd=area under v–t=vtr+v22av = \dfrac{\Delta x}{\Delta t} \qquad a = \dfrac{\Delta v}{\Delta t} \qquad d = \text{area under } v\text{--}t = v t_r + \dfrac{v^2}{2a}v=ΔtΔx​a=ΔtΔv​d=area under v–t=vtr​+2av2​
  • ·Δx = displacement in metres (m) — the straight-line change in position
  • ·which can be negative; Δv = final velocity − initial velocity (m/s); Δt = the time interval (s). The Δ ('delta') means 'change in'
  • ·so always subtract the starting value first. Speed is the magnitude of velocity: a scalar
  • ·always positive
  • ·and computed from total distance rather than displacement. On a graph the same divisions are rise ÷ run: metres over seconds gives m/s (a velocity); m/s over seconds gives m/s² (an acceleration). Area under a v–t line is m/s × s = m
  • ·a distance.

Common mistake

Assuming stopping distance scales with speed. Only the thinking part does — the braking part is v2/2av^2/2av2/2a, so it quadruples when you double the speed. The same slip in graph form is reading a graph's HEIGHT when the answer lives in its slope or its area, and forgetting that a flat line means 'stopped' on an x–t graph but 'cruising' on a v–t graph.

What to remember

  • ·Velocity is the slope of the position–time graph; acceleration is the slope of the velocity–time graph. One motion, differentiated twice.
  • ·The area under a velocity–time graph is the distance travelled — rectangles for steady velocity, triangles for steady acceleration.
  • ·Speed uses total distance and is always positive; velocity uses displacement, so a round trip averages exactly zero velocity however fast you went.
  • ·Stopping distance =vtr+v2/2a= v t_r + v^2/2a=vtr​+v2/2a: the thinking part doubles when you double the speed, the braking part quadruples.
  • ·A flat line means opposite things on the two graphs — always check which one you are reading.